4^4444 + 3^333 is divided by 7

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4^4444 + 3^333 is divided by 7

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n/a

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ans-3

ans-3

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1+6=7, so remainder is 0

1+6=7, so remainder is 0

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The value of n is not the same one is 1111 and next is 111 and so how come its remainder will be zero

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4^4444 + 3^333 divided by 7

4^4444 = 2^8888 and 2^3 / 7 gives a remainder = 1
8888 = 3*2062 + remainder 2
hence 4^4444 divided by 7 gives a remainder = 2^2 = 4

3^3 = 27 when divided by 7 gives a remainder = 6 or -1
and (-1)^111 = -1
hence remainder = +4 - 1 = 3

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abe sale galat multiply krna nhi ata...CAT nikalne chala hai

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4^4444 + 3^333 divided by 7

4^4444 + 3^333
-------------------------    = 4^(3(1448)  + 3^(6(56)) * 3^3
7                           --------------------------------------------         =      (1+6)/7 =7/7.
7

therefore remainder is 0 zero.

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4^4444 + 3^333 divided by 7

3^3 = 27 when divided by 7 gives a remainder = 6 or -1 here hw wil get -1 as remainder as far i knw i got 7 as remainder bt hw cm -1..? plz explain. nxt.. 4^4444 = 2^8888 and 2^3 / 7 gives a remainder = 1 8888 = 3*2062 + remainder 2 hence 4^4444 divided by 7 gives a remainder = 2^2 = 4 here in the above 8888 = 3*2062 + remainder 2..here y u tuk remainder 2..? and 3*2062 iswt..? an hw u considedred it.. i dint get u plz elaborate ur explanation plz..

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