# Hey guys this is...

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Hey guys this is a question from the arun sharma alligations chapter ...do let me know how to solve this using the alligations formula :-

A bag contains a total of 105 coins of Rs 1,50 p and 25 p denominations .Find the number of coins of Re 1 if there are a total of 50.5 rupees in the bag and it is known that the number of 25 paise coins are 133.33 % more than the number of 1 rupee coins .

a) 56
b)25
c)24
d)none of these
Incognito
The ans is none. from the

The ans is none.

from the given data we will get two equations 2.33X+Y=105 and
5.33X+y=210

from equation 1 we can determine that 2.33X is odd(any no. multiplied by odd no. results odd no) so y must be even.
but in 2nd equation Y should be even then only we will get the sum as a even no.
so 1 and 2 are contraversial to each other
so ans is d

Incognito
ans is d

ans is d

Incognito

the number of coins of Re 1 are 24, that of 50p are 25 and 25p are 56.

i) 24+25+56= 105 ( first condition)

ii) (1x24) + ( 0.5 x25) + (0.25 x 56) = 50.5 ( second condition)

iii) 56/24 = 2.3333 ( third condition)

to solve this, make three simultaneous equations for all the three conditions given and solve them, you shall get the required answer.

( @ the incognito solver: notice that the question says 133.33 % more... that means that the 25p coins are 233.33 % of the number of Re1 coins, be careful with the language always)

Incognito
ans is d

ans is d

Incognito
I feel the answer is B

I feel the answer is B

Incognito

It is 100% --------------->>>>>>>>>>>>> 24

The 1 Re coins are 24
50Paise cions are 25
25Paise cions are 56

Incognito
test

test 24 is the correct answer