# QBM025

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Q1. A mixture contains milk and water in the ratio 5 : 1. On adding 5 litres of water, the ratio of milk and water becomes 5 : 2. The quantity of milk in the mixture is:

Q2. The ages of Vivek and Sumit are in the ratio 2 : 3. After 12 years, their ages will be in the ratio 11 : 15. The same of Sumit is:

Q3. Rs. 500 are to be divided among A, B, C and D. A and B together get thrice as much as C and D together, B gets 4 times of what C gets and D gets 1.5 times as much as C gets. Find the share of A.

Q4. A mixture contains brandy and water in the ratio 8 : X. When 33 lts of mixture and 3 lts of water are mixed the ratio brandy and water becomes 2 :1. The value of X is

Q5. In two alloys, aluminum and iron are in the ratios of 1:4 and 1:3. After alloying together 10kg of the first alloy, 16 kg of the second and several kilograms of pure almunium, an alloy was obtained in which the ratio of almunium to iron was 3:2. Find the weight of the new alloy

Q6. Two boxes A and B were filled with a mixture of rice and dal .in A in the ratio 5 : 3, and in B in the ratio of 7:3. What quantity must be taken from the first to form a mixture that shall contain 6kg of rice and 3 kg of dal?

Q7. One-fourth of the boys and three-eights of the girls in a school participated in the annual sports. What fractional part of the total student population of the school participated in the annual sports?

Q8. The prices of a scooter and a television set are in the ratio 3 : 2. If a scooter costs Rs 6000 more than television set, the price of the television set is:

Q9. If 2A = 3B and 4B = 5C, then A : C is.

Q10. The present ages of A and B are as 6 : 4. Five years ago their ages were in the ratio 5 : 3. Find their present ages.

Q11.Bag A contains m coins of 50-paisa and n coins of 25-paisa. Bag B contains m coins of 25-paisa and n coins of 50-paisa. If 3 coins of 50-paisa from bag A are put into bag B and 3 coins of 25-paisa from bag B are put into bag A, the total value in each bag is the same. What is the minimum value of the money in Bag A initially?

Q12.A number is a summation of three parts in the ratio 1:2:7 where the largest part is 49. This number is

Q13.If x : y = 4 : 5, find the value of (6x + 3y) : (2x + y)

Q14. A's money is to B,s money as 4 : 5 and B's money is to C's money as 2 : 3. If A has Rs 800, C has:

Q15. If 20 men or 24 women or 40 boys can do a job in 12 days working for 8 hours a day, how many men working with 6 women and 2 boys take to do a job four times as big working for 5 hours a day for 12 days?

Q16. The ratio of father's age to his son's age is 4 : 1. The product of their ages is 196. The ratio of their ages after 5 years will be:

Q17. If yz : zx: xy = 1 : 2 : 3, then find x/yz : y/xz

Q18. A precious stone weighing 35 grams worth Rs. 12, 250 is accidentally dropped and gets broken into two pieces having weights in the ratio of 2 : 5. If the price varies as the square of the weight then find the loss incurred

END

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Last seen: 10 years 3 weeks ago
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Q1. 25 litres
Q2. 48 years
Q3. Rs.175
Q4. 3
Q5. 35
Q6. Not possibe
Q8. 12000
Q9. 15 : 8
Q10. 30, 20
Q11. Rs.3.75
Q14. Rs. 1500
Q15. 2 men
Q16. 11 : 4
Q17. 4: 1
Q18. Rs. 5000

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Last seen: 10 years 43 weeks ago
Joined: 2007-06-08
Q7- 1/3

Q7- 1/3

Can u please tell me how u approched for the Q11..

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Last seen: 10 years 3 weeks ago
Joined: 2006-08-30
Bag A: total rupee = .5m +

Bag A: total rupee = .5m + .25n
Bag B: total rupee = .25m + .5n

After 3 coins of 50-paisa from bag A are put into bag B and 3 coins of 25-paisa from bag B are put into bag A
Bag A: total rupee = .5(m-3) + .25(n+3)
Bag B: total rupee = .25(m+3) + .5(n-3)

And Now both are same i.e
.5m – 1.5 + .25n + .75 = .25m + .75 + .5n - 1.5
=>.25m-.25n=0
=>m = n

As we are taking 3 coins from bag A to B (and also from B to A) there shd be at least 6 coins of .5 and 3 coins of .25
So Total value = 3 + .75 = 3.75

Sandeep (not verified)
Thanks

Thanks

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Last seen: 10 years 43 weeks ago
Joined: 2007-06-08
How u co-relate these

How u co-relate these two:

"And Now both are same i.e
.5m – 1.5 + .25n + .75 = .25m + .75 + .5n - 1.5
=>.25m-.25n=0
=>m = n"

and

"As we are taking 3 coins from bag A to B (and also from B to A) there shd be at least 6 coins of .5 and 3 coins of .25"

You may be right but i am unable to understand logic.

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Last seen: 10 years 3 weeks ago
Joined: 2006-06-08
it is given in the question

it is given in the question that after the transaction the total value in each bag is the same

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Last seen: 10 years 43 weeks ago
Joined: 2007-06-08
Thanks

YES I got it thanks, But i think there will be some alternate method to do this.

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Last seen: 10 years 20 weeks ago
Joined: 2008-04-28
CAN  ANYONE  TELL  ME

CAN  ANYONE  TELL  ME  HOW  TO  DO  5TH  AND  7TH  SUM  PLEASE..........................

Incognito (not verified)
@anjana1490

Q5. In two alloys, aluminum and iron are in the ratios of 1:4 and 1:3. After alloying together 10kg of the first alloy, 16 kg of the second and several kilograms of pure almunium, an alloy was obtained in which the ratio of almunium to iron was 3:2. Find the weight of the new alloy.

ANS:

10 kg of the first alloy cotains 2kg of al and 8kg of iron
16 kg of the second alloy cotains 4kg of al and 12kg of iron
Let the pure al mixed = x kg

Total al in final mixture = 6+x
Total Iron in final mixture = 20

and the final ratio = 3/2

=> (6+x)/20 = 3/2

=>12 + 2x = 60

=>2x = 48

=> x = 24kg

Incognito (not verified)
@anjana1490

Q7. One-fourth of the boys and three-eights of the girls in a school participated in the annual sports. What fractional part of the total student population of the school participated in the annual sports?

ans:

cannot be determined