Hi Could anyone please help me with the question posted If Rama's income is 20% more than Shyama's income, by what percentage is Shyama's income less than Rama's? I want to know how do we find in general "x is what percentage of y" in the above case how did we arrive that 20 is1/6th or 16.66 %. Please help me with this very basic doubt. __________________
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Please read the chapter and remember the basic fraction/percentages given
@ http://www.cat4mba.com/math-e-boom/vedic-mathematcis-1
Given Rama's income is 20% more than Shyama's income
Let Shyam’s income = 100, then Rama’s income is 120 (as its 20% more than Shyam’s income)
So Shyam’s income is 20 (= 120-100) less than Rama’s income.
Now rest of the Question is “ by what percentage is Shyama's income less than Rama's?”
We know Shyam’s income is 20 less than Rama’s income where Rama’s income is 120.
So if we consider Rama’s income as our base of calculation then
Shyam’s income is 20 less than Rama’s income where Rama’s income is 120
=> Shyam’s income is 1/6(20/120) less than Rama’s income where Rama’s income
=> Shyam’s income is 16.66% (1/6 x 100) less than Rama’s income where Rama’s income
Please let me know if it s clear now.
(Any how you can join the class room group where we discuss all the basics in details and have just started the number system)
If Ist quantity is x% more/Less than the IInd quantity then IInd quantity is x/100+,-,x% less/more than the other quantity.
required%=20/100+20=16.66%
U can go through the K.Kundan/P.Pandey book these chapters are very well disussed in this book followed by good exerciese with detailed soln.
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