CAT4MBA

there are 128 boxes

atleast 120 chocolates

at max--------->144 chocolates

therefore the range is 144-125(including both ) = 25

least number of boxes containing the same number of chocolates 128/25 = 5 + remainder 3(which can be divided into 3 other boxes)

hence the answer is 5....

ans must be 6...

regards,
shaheen

@ Shaheen

can u explain?????????

Could not understand the question

but There ' ll be 6 boxes containing equal number of chocolates(any number between 120 - 144) - 3 cases

an  There ' ll be 5 boxes containing equal number of chocolates(any number between 120 - 144) -   22 cases

i could attach a document here...so i attached it in a new thread... ;-)

regards,
shaheen

i couldn't attach a document here...so i attached it in a new thread... ;-)

regards,
shaheen

hi humraj,

chk out the following attachment, n i think the ans will be clear to u...

regards, shaheen

@Shaheen

Thnx a lot..........