leap plzzzzzzz solve

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Incognito

a hare makes 4 leap in the same time in which a dog makes 3 but 2 leaps of the dog cover as much distance as 3 leaps of hare; how many leaps will the dog have to make before catching the hare,supposing the hare to have a start of 60 leaps.

ans is 360

Incognito

in unit time hare makes 4 hops and dog makes 3 hops
distance covered by hare in single hop  = h
-do-                           dog        -do-             = d

2d=3h given

hence, hare speed per unit time = 4h/1 = 4h
hence, dog speed per unit time = 3d/1 = 3d

dog catches hare in time t

60h + 4h*t = 3d*t
60h + 4h*t = 3*(3/2)*h*t

60 + 4t = 9/2 * t
t = 120

hops done by dog in unit time = 3
hops done by dog in 120 time unit = 3*120 = 360

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Last seen: 6 years 19 weeks ago
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unit time of dog =3 dog leaps

unit time of dog =3
dog leaps 120 *3 = 360

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Last seen: 5 years 43 weeks ago
Joined: 2012-02-10
360*3 = 1080

360*3 = 1080

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