Q) How to find the product of any divisor??for eg question of the type: find the product of the divisors of 316???????
n/a
i think attached file is enough for u
Little Star
sorry ..but i cant see any attached file....
OK I ATTACHED HERE SECONDTIME
LITTLE STAR
Just copyin from http://www.cat4mba.com/content/number-divisors
Please read the 5th point carefully.
Let N = am x bn x cp x . . .
1. Number of divisors of any natural number N is (m+1) (n+1) (p+1)
Example: 63504 = 72 x 24 x 34
So the number of divisors of 63504 = (2+1) (4+1) (4+1) = 75
Remember this includes the number 63504 and 1 also.
2. Number of even divisors = Number of divisors which are even.
Let N = 2m x bn x cp x dq x . . .
Then number of even divisors = m (n+1) (p+1) (q+1)
Number of even divisors = 4 x 5 x 3 = 60
3. Number of odd divisors = Number of divisors which are odd
It’s same as calculating number of divisors of the number with out all the powers of 2.
For 63504, number of odd divisors = 3 x 5 = 15
4. Sum of all the divisors of a natural number N is
[(am+1 -1) x (bn+1 -1) x (cp+1 – 1)] / (a –1) (b –1) (c –1)
5. Product of the divisors of a natural number N is
Nx/2 where x = (m+1)(n+1)(p+1)
thanks..
316 = 4 x 79 = 2^2 x 79^1 x/2 = 3
So prodcut = 316^3
Am I right???
More information about formatting options
i think attached file is enough for u
Little Star
n/a
sorry ..but i cant see any attached file....
n/a
OK I ATTACHED HERE SECONDTIME
LITTLE STAR
n/a
Just copyin from http://www.cat4mba.com/content/number-divisors
Please read the 5th point carefully.
Let N = am x bn x cp x . . .
1. Number of divisors of any natural number N is (m+1) (n+1) (p+1)
Example: 63504 = 72 x 24 x 34
So the number of divisors of 63504 = (2+1) (4+1) (4+1) = 75
Remember this includes the number 63504 and 1 also.
2. Number of even divisors = Number of divisors which are even.
Let N = 2m x bn x cp x dq x . . .
Then number of even divisors = m (n+1) (p+1) (q+1)
Number of even divisors = 4 x 5 x 3 = 60
3. Number of odd divisors = Number of divisors which are odd
It’s same as calculating number of divisors of the number with out all the powers of 2.
For 63504, number of odd divisors = 3 x 5 = 15
4. Sum of all the divisors of a natural number N is
[(am+1 -1) x (bn+1 -1) x (cp+1 – 1)] / (a –1) (b –1) (c –1)
5. Product of the divisors of a natural number N is
Nx/2 where x = (m+1)(n+1)(p+1)
n/a
thanks..
n/a
316 = 4 x 79
= 2^2 x 79^1
x/2 = 3
So prodcut = 316^3
Am I right???
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