How to..

Q) How to find the product of any divisor??
for eg question of the type: find the product of the divisors of 316???????

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      i think attached

 

 

 

i think attached file is enough for u

Little Star

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   sorry ..but i cant

 

 sorry ..but i cant see any attached file....

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OK I ATTACHED HERE

OK I ATTACHED HERE SECONDTIME

LITTLE STAR

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please check the Number of divisors notes

Just copyin from http://www.cat4mba.com/content/number-divisors

Please read the 5th point carefully.

Let N = am x bn x cp x . . .    

1. Number of divisors of any natural number N is (m+1) (n+1) (p+1)

 Example: 63504 = 72 x 24 x 34

So the number of divisors of 63504 = (2+1) (4+1) (4+1) = 75

Remember this includes the number 63504 and 1 also.

2. Number of even divisors = Number of divisors which are even.

Let N = 2m x bn x cp x dq x . . .    

Then number of even divisors = m (n+1) (p+1) (q+1)

So for the number 63504,

Number of even divisors = 4 x 5 x 3 = 60

3. Number of odd divisors = Number of divisors which are odd

It’s same as calculating number of divisors of the number with out all the powers of 2.

For 63504, number of odd divisors = 3 x 5 = 15

4. Sum of all the divisors of a natural number N is 

                                [(am+1 -1) x (bn+1 -1) x (cp+1 – 1)] / (a –1) (b –1) (c –1)

5. Product of the divisors of a natural number N is

                                                               Nx/2 where x = (m+1)(n+1)(p+1) 

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   thanks..

 

 thanks..

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Thanks @ alivia

316 = 4 x 79
= 2^2 x 79^1
x/2 = 3

So prodcut = 316^3

Am I right???

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