## QBM023 math question

Please help in solving the following question. Q8. A piece of diamond is broken into 3 pcs. The weight of 3 pcs. In the ratio of 1:2:3. Price of piece of diamond is proportional to the square of its weight. Find the price of the original piece, if loss due to breaking is Rs.21000. Is it a sitter as written on this site ??

## Let the initial weight be

Let the initial weight be n
Then the price P_{1}=Kn^{2}
After the break up three piece weight will be n/6 , n/3 and n/2
So the sum of the prices will be K[ (n/6) ^{2} + (n/3) ^{2} + (n/2) ^{2}] (let it be P)
given the loss is 21000, so 1 - P = 21000
Now do the calculations to get Kn^{2} which is the original price

Is it a sitter as written on this site ??Now don't you think so