## BASKET question from FLTM008

There are 100 players numbered 1 to 100 and 100 baskets numbered 1 to 100. The first player puts one ball in every basket starting from the first basket (i.e. in baskets numbered 1, 2 , 3) . The second player puts 2 balls each in every second basket starting from the second ( i.e. in baskets numbered 2,4,6. . .) The third player puts three balls each in every third basket starting from the third , and so on till the hundredth player. 1. Which basket will have the maximum number of balls? a.96 b.98 c.100 d.none e.Not Attempted 2. How many baskets will finally have exactly twice the number of balls as the number on the basket itself? a.8 b.6 c.4 d.2 e.Not Attempted 3. In how many baskets will exactly two players put the balls? a.50 b.25 c.15 d.None e.Not Attempted How to solve the above question In this test I scored 32 and it was my first attempt – how good is it

## the first question reduces

the first question reduces to : which number has the max. number of divisors. of the three 96 has the max divisors. however None of these could also be an answer.

## the first question reduces

the first question reduces to : which number has the max. number of divisors
Rather it should be - which number has the max. sum of all its divisors

## yes! missed that part.

yes! missed that part.

## reply

1st qs->max sum of divisers which is for 96 3rd qs->no of prime b/w 1&100

## reply

2nd qs-> buckets 3rd,6th,12th,24th,48th,96th 6 of them will have twice the no. of balls..

## way to solve fltoo8

for 1st and 2nd question, ans lie in calculating the sum of factors including that number and 1 also, while for the third one ans will be the total number of primes