## intresting one...

hii all..herz an intrestin question...
Q How many digits are used to make a book containing 500 pages?
wot cud b da ansr..???
um gettn 1791 as ansr..

## 1 digit – 102 digit – 2

1 digit – 10
2 digit – 2 x 90 = 180
3 digit – 3 x 401 = 1203
Total 1393

## TWO SOLUTIONS

1.
from page no. 1-9 : 1x10=10
from page no. 10-99 : 2x90=180
from page no. 100-500 : 3x401=1203
10+180+1203= 1393
2.
0 1 2 3 4 5 6 7 8 9
10 digits are used.
what u say.....

## somebody tell me where did

somebody tell me where did 91-99 go !

## yeps u r rite...

how i find dat....lemme xplain...
each number frm 1 to 9 comes 20 times from 1 to 99...from here we can calculate no of digits i.e 20*9=180 digits
n frm 1 to 99, "9" zeroes are there..i.e in 10,20,30...90
now lets cum to 3 digits....strting from 100 to 199...we vil add zeroes of 100 at later stage...!!!1
so 1 wil cum at 100's place at 100 times
and 1 wil cum at 10s place...10 times
and 1 wil cum at unit's place=10 times
so no of ones=180
now total no of ones=100+10+10=120
now lets calculate other digits...
no of twos vil cum=20 times(10+10, same funda as we hv calculated in finding no of ones except there is no 100's place)
so...rest of the digits except 1 wil cum 20 times..
so total no of digits included 2 =9*20=180
so total no of digits from 100 to 199=120+180=400
i.e 400+2(no of zeroes in 100)=402
this funda vil go on..n vil calculate no of digits from 200-300 which is again 402
nd 300-400 again 402
nd 400-500 again 402
so 402*4=1608
nd final ansr is 1608+180=1788 no of digits..
correct mee if um wrong..
thnx..

## Please see it again

i think the answer is 1392

## Solution:

Pages 1-9 : 9
Pages 10-99 : 2*90 = 180
Pages 100-500 : 3*401 = 1203
Therefore, total no. of digits used = 9+180+1203 = 1392.

## hii all

hii.. wots wrong in ma aaproachh.....?????

## you have written solution is

your written solution is very complex. but if u elobrate it i can tell u wats wrong.