## Question from QBM034

What is the answer Q9. In a race of 200 meters, A beats S by 20 meters and N by 40 metres. If S and N are running a race of 100 metres with exactly the same speed as before, then by how many metres will S beat N? (1)11.11 metres (2) 10 metres (3) 12 metres (4) 25 metres

## solution

Q9. In a race of 200 meters, A beats S by 20 meters and N by 40 metres. If S and N are running a race of 100 metres with exactly the same speed as before, then by how many metres will S beat N? (1)11.11 metres (2) 10 metres (3) 12 metres (4) 25 metres soln A S N 200 180 160 means when A runs 200, s runs 180 and N runs 160 if race is of 100 mtr thn A S N 100 90 80 rite.....!!! coz ratio vil remain same now in order to make S and N 100...coz ve have to compare both S and N in 100 mtr race..so its becum imperative to make both of the units same... so multiply both of them with 10/9 so that S=100 and N=88.88 now tke the diffrence of S and N =11.11 so ansr is (a)

## solution

A S N 200 180 160 (given) now for 100 mtr race..ratio vil remain same.. new distance becums A S N 100 90 80 in order to compare for S and N for 100 mtr race...coth should complete ther 100 mtr race....so S will complete its race by multiplying it with 10/9 and N will complete its 100 mtr race by multiplying by 10/9(ratio should be same) so distance of N becums==80*10/9=88.88 now take the difference S-N=100-88.88=11.12 i.e (a)

## soln

A S N 200 180 160(given) in 100 mtr race A S N 100 90 80(ratio will remain same) so in order to make S and N as 100 mtr we have to multiply by 10/9 so that S becums 100 and N becums 80*10/9=88.88 so diff S-N=100-88.88=11.12 i.e option (a)